Question

A gas contains 4g ch4 and 4g of he what is the.Volume.Of stp

Answer 1

CH4mol.mass = 16g/mol  

4.0g / 16g/mol = 0.25 mol.  

He mol.mass = 4.0g/mol.  

2.0g / 4g/mol = 0.5 mol.  

Total moles at STP = 0.75.  

At STP 1.0mole occupies 22.4 L volume.  

0.75mol x 22.4L/mol. = 16.8 L (= C: 17L) at STP.