A gas cylinder can withstand a pressure of 14.9 atm. The pressure gauge of the cylinder shows 12 atm at 27°C .Due to a fire in the building, the temperature increases suddenly. At what temperature will the cylinder explode?
Answers
Answered by
27
p₁=12 atm
t₁=27'C or 273+27=300 k
p₂=14.9 atm
∴ t2=(p₂ x t₁)/p₁
(14.9 x 300)/12
=372.5 K or 372.5 -273
=99.5'C
t₁=27'C or 273+27=300 k
p₂=14.9 atm
∴ t2=(p₂ x t₁)/p₁
(14.9 x 300)/12
=372.5 K or 372.5 -273
=99.5'C
Similar questions