Chemistry, asked by nadeemnadeemaziz, 10 months ago

A gas cylinder containing 0.11 m 3 of air at 15 °C exerts a force of 24 000 N on an area
of 0.024 m2 .

a. What is the pressure exerted by the gas in kilopascals?

b. Using the information above and the value calculated in (a), calculate the
volume of the gas at SATP?

Answers

Answered by saifmakhamreh10
1

Answer:

hi

Explanation:

ccording to ideal gas equation

At point B:

PV=nRT;V=  

3

1×0.082×600

​  

=16.42 lit

Also as pressure is same at A and C so  

V  

A

​  

 

V  

C

​  

 

​  

=  

T  

A

​  

 

T  

C

​  

 

​  

=  

1

3

​  

 

⇒V  

C

​  

=3×V  

A

Answered by saivivek16
0

Explanation:

Aloha !

 \text { This is Sweety Adihya } ❤️

Concept used here :-

Chemistry

Question:-

A gas cylinder containing 0.11 m 3 of air at 15 °C exerts a force of 24 000 N on an area

of 0.024 m2 .

a. What is the pressure exerted by the gas in kilopascals?

b. Using the information above and the value calculated in (a), calculate the

volume of the gas at SATP?

Answer:-

We know that,

PV=nRT

This is ideal gas equation.

Where,

p-pressure

v-volume

n-no.of moles

R-gas constant

T-temperature

P×3=1×0.024×15

p×3=0.024×15

p×3=0.36

p=0.36/3

p=0.12

Hope it will help you

@ Sweety Adihya

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