A gas cylinder containing 0.11 m 3 of air at 15 °C exerts a force of 24 000 N on an area
of 0.024 m2 .
a. What is the pressure exerted by the gas in kilopascals?
b. Using the information above and the value calculated in (a), calculate the
volume of the gas at SATP?
Answers
Answered by
1
Answer:
hi
Explanation:
ccording to ideal gas equation
At point B:
PV=nRT;V=
3
1×0.082×600
=16.42 lit
Also as pressure is same at A and C so
V
A
V
C
=
T
A
T
C
=
1
3
⇒V
C
=3×V
A
Answered by
0
Explanation:
Aloha !
❤️
Concept used here :-
Chemistry
Question:-
A gas cylinder containing 0.11 m 3 of air at 15 °C exerts a force of 24 000 N on an area
of 0.024 m2 .
a. What is the pressure exerted by the gas in kilopascals?
b. Using the information above and the value calculated in (a), calculate the
volume of the gas at SATP?
Answer:-
We know that,
PV=nRT
This is ideal gas equation.
Where,
p-pressure
v-volume
n-no.of moles
R-gas constant
T-temperature
P×3=1×0.024×15
p×3=0.024×15
p×3=0.36
p=0.36/3
p=0.12
Hope it will help you
@ Sweety Adihya
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