A gas cylinder filled with hydrogen holds 50 gm of the gas .The same cylinder holds 200 gm of gas A and 500 gm of gas B considering the same conditions of temperature and pressure in the cylinder , calculate the relative molecular masses of gases A and B
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the molecular mass of gas A is 8 gm and the molecular mass of gas B is 20 gm
since let the pressure inside the cylinder be p and temperature be T and volume of cylinder be v
now given mass of hydrogen is 50 gm and molecular mass of hydrogen = 2 gm
therefore no. of moles present in cylindr is=50/2=25
now according to ideal gas equation pv=nRT
v=25RT/p............1
now let the molecular mass of gas A be mA
and given mass is 200gm
according to ideal gas equation
pv=nRT
v=200/mA×RT/p........2
from 1 and 2
25RT/p=200/mA×RT/p
mA=8gm
similarly u can find molecular mass of gas B
since let the pressure inside the cylinder be p and temperature be T and volume of cylinder be v
now given mass of hydrogen is 50 gm and molecular mass of hydrogen = 2 gm
therefore no. of moles present in cylindr is=50/2=25
now according to ideal gas equation pv=nRT
v=25RT/p............1
now let the molecular mass of gas A be mA
and given mass is 200gm
according to ideal gas equation
pv=nRT
v=200/mA×RT/p........2
from 1 and 2
25RT/p=200/mA×RT/p
mA=8gm
similarly u can find molecular mass of gas B
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