Question

A gas  cylinder  filled with  hydrogen holds 50 gm of the gas .The same  cylinder holds 200 gm of  gas  A and  500  gm of  gas B considering the same  conditions of  temperature  and pressure  in the  cylinder , calculate  the  relative molecular  masses of gases A and B

Answer 1

the molecular mass of gas A is 8 gm and the molecular mass of gas B is 20 gm
since let the pressure inside the cylinder be p and temperature be T and volume of cylinder be v
now given mass of hydrogen is 50 gm and molecular mass of hydrogen = 2 gm 
therefore no. of moles present in cylindr is=50/2=25 
now according to ideal gas equation pv=nRT
                                                      v=25RT/p............1
now let the molecular mass of gas A be mA
and given mass is 200gm
according to ideal gas equation 
pv=nRT
v=200/mA×RT/p........2
from 1 and 2
25RT/p=200/mA×RT/p
mA=8gm
similarly u can find molecular mass of gas B

Answer 2

Answer:

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Explanation:

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