A gas enclosed in a cylinder fitted with a piston is expanded so that its volume increases from 5
litre to 6 litre at constant pressure of 1.013 × 105 Pa. Find the work done by the gas in this
process.
Answers
Answered by
2
Explanation:
PV
5/3
=C
Thus, γ=
3
5
ΔQ
1
=nC
P
ΔT
=n
γ−1
γR
ΔT=
γ−1
γPΔV
=
2
5
×10
5
(7×10
−3
)=1750 J
ΔQ
2
=nC
V
ΔT
=n
γ−1
R
ΔT=
γ−1
VΔP
=
3
2
(
32
1
−1)×10
5
(8×10
−3
)
=−
8
9300
J
ΔQ=ΔQ
1
+ΔQ
2
=1750−
8
9300
≈588 J
Similar questions