a gas enclosed in a cylinder undergoes in a cyclic process as shown in the figure. calculate the total heat added to the system.
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Hey.
Here is your answer.
as dQ=dU + dW
and for a cyclic process the change in internal energy is zero.
so, dU=0
hence, dQ=dW
so, dQ=∆p×∆V
so, dQ=(5-2)×(0.50-0.10)×10^5=3×0.4×10^5
so, dQ=1.2×10^5 Nm
Thanks.
Here is your answer.
as dQ=dU + dW
and for a cyclic process the change in internal energy is zero.
so, dU=0
hence, dQ=dW
so, dQ=∆p×∆V
so, dQ=(5-2)×(0.50-0.10)×10^5=3×0.4×10^5
so, dQ=1.2×10^5 Nm
Thanks.
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