Question

A gas engine has a swept volume of 300 cm3 and clearance volume of 25 cm3. Its volumetric efficiency is 0.88 and mechanical efficiency is 0.90 solution

Answer 1

Answer:

A gas engine has a swept volume of 300 cm3 and clearance volume of 25 cm3. Its volumetric efficiency is 0.88 and mechanical efficiency is 0.90. The volume of the mixture taken in per stroke is.

Answer 2

Answer:$\therefore \text { Actual intake volume }=300 \times 0.88=264 \mathrm{~cm}^3$

Explanation: A gas engine has a swept volume of 300 cm3 and clearance volume of 25 cm3. Its volumetric efficiency is 0.88 and mechanical efficiency is 0.90 solution

$\text { Volumetric efficiency }=\frac{\text { Actual intake volume }}{\text { Swept volume }}$

$\text { Swept volume }=300 \mathrm{~cm}^3 \text {, Volumetric efficiency, } \eta_{\mathrm{v}}=0.88 \text {. }$

$\text { Volumetric efficiency }=\frac{\text { Actual intake volume }}{\text { Swept volume }}$

$\Rightarrow 0.88=\frac{\text { Actual intake volume }}{300}$

$\therefore \text { Actual intake volume }=300 \times 0.88=264 \mathrm{~cm}^3$

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