A gas expands by 0.25 litres at a constant pressure of 0.25 atm.Calculate the work done
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change in volume (ΔV) = 0.25l = 2.5×10^(-4) m³
pressure (p)= 0.25 atm = 0.25×101.3×10³ Pa
Work done = p.ΔV = 2.5×10^(-4)×0.25×101.3×10³ = 6.33 J
pressure (p)= 0.25 atm = 0.25×101.3×10³ Pa
Work done = p.ΔV = 2.5×10^(-4)×0.25×101.3×10³ = 6.33 J
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Explanation:
delta v =0.25l how it convert to m3
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