Question

A gas expands from 1 litre to 10 litre at constant temperature against external pressure

of 0.5 atm find out the work done.

1. 455.85J 2.-455.85J

3. -555.85J 4.555.85J​

Answer 1

$\large\underline{\bigstar \: \: {\sf Given-}}$

• Gas expands from ${\sf (V_1)=1L\: to \: (V_2)=10L}$
• External Pressure (P) = 0.5 atm

$\large\underline{\bigstar \: \: {\sf To \: Find-}}$

• Work done (W)

$\large\underline{\bigstar \: \: {\sf Formula \: Us d-}}$

$\Large\color{violet}\underline{\boxed{\sf W=-P\Delta V}}$

$\large\underline{\bigstar \: \: {\sf Solution-}}$

$\implies{\sf W=-P\Delta V}$

$\implies{\sf W=-0.5×(10-1) }$

$\implies{\sf W=-0.5×9}$

$\implies{\sf W=4.5\:L-atm }$

$\implies{\sf W=4.5×101J }$

$\color{red}\implies{\sf W=454.5J}$

$\large\underline{\bigstar \: \: {\sf Answer-}}$

Work done is $\color{red}{\sf 454.5J}$