Question

A gas expands in volume from 2lit to slit against as pressure at 1atm as concentrate temp the work don by a gas will be

Answer 1

Explanation:

As we know that, work done in isothermal expansion is given as-

W=−nRTln

V

1

V

2

=−2.303nRTlog

V

1

V

2

Given:-

n= No. of moles =1 mole

R= Gas constant =2 cal

T= constant temperature associated with the process =25℃=(25+273)K=298K

V

1

= Initial volume =15L

V

2

= Final volume =50L

∴W=−2.303×1×2×298×log(

15

50

)

⇒W=−1372.588×(log10−log3)

⇒W=−1372.588×0.523=−717.86≈=−718 cal

Hence the work done will be −718 cal