Question

→ A gas ‘G’ is contained in a vessel of capacity 40 litres and subjected to a
pressure of 20 atm. When this container is connected to a second empty container
of the same capacity, find the pressure that will be acting on the gas ‘G’ in both the
containers if the temperature is kept constant.

Answer 1

Answer:

Given :

• A gas 'G' is contained in a vessel of capacity 40 litres and subjected to a pressure of 20atm.

• when this contained is connected to a second empty container of the same capacity.

Find :

• The pressure that will be acting on the gas 'G' is both the containers if the temperature is kept constant.

Solution :

Initial conditions :

• V1 = 40 litres,
• P1 = 20 atm.

Final conditions :

• V2 = (40 + 40) = 80 litres,
• P2 = ?

Since, Temperature is kept constant,

Applying BOYLE'S LAW

P1 V1 = P2 V2

20 × 40 = P2 × 80

P2 = 20 × 40 / 80 => 800 / 10 => 10 atm

∴ The pressure of the gas in both the containers =>

10 atmosphere.

⭐________________________

Explanation:

@GENIU$

Answer 2

A gas ‘G’ is contained in a vessel of capacity 40 litres and subjected to a

pressure of 20 atm. When this container is connected to a second empty container

of the same capacity, find the pressure that will be acting on the gas ‘G’ in both the

containers if the temperature is kept constant.

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