Question

a gas had volume of 1.2L and temperature of 300K. If the temperature change to 250K, the new volume will be
_____ L

Answer 1

Answer:

Explation

The equation is  

V

1

T

1

=

V

2

T

2

, where  

V

is volume and  

T

is temperature in Kelvins.

Known

V

1

=

0.5 L

T

1

=

20

∘

C

+

273.15

=

293 K

T

2

=

150

∘

C

+

273.15

=

423 K

Unknown

V

2

Solution

Rearrange the equation to isolate  

V

2

. Substitute the known values into the equation and solve.

V

2

=

V

1

T

2

T

1

V

2

=

(

0.5

L

×

423

K

)

293

K

=

0.7 L

rounded to one significant figure

Answer 2

Answer:

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