Question

A gas has a pressure of 1080mmHg.if the volume is decreased by 40%, find the new pressure of the gas.

Answer 1

Answer:-

Let the Initial Volume of the gas be "V".

Given:

Initial Pressure (P1) = 1080 mm Hg.

And the Volume is decreased by 40%.

→ Final Volume = [(100 - 40)/100]*V = 60V/100 = 3V/5.

We know that,

Boyle's law of gases states that at constant temperature the pressure of a gas is inversely proportional to it's Volume.

$\implies \sf \large{ \: P \: \: \alpha \: \: \frac{1}{V} }$

→ PV = k (Constant)

$\sf \implies \: P_{1}V _{1} = P _{2}V _{2}$

→ (1080)(V) = (P2)(3V/5)

→ P2 = 1080V/(3V/5)

→ P2 = 1080V * (5/3V)

→ P2 = 1800 mm Hg.

Hence, the pressure of the gas increases to 1800 mm Hg.