a gas has vapour density 32. what will be the mass of 5.6L of the gas? ans.-16g
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Answered by
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VD of gas = 32
therefore molar mass=32×2=64g
since 22.4l=1mole
therefore 5.6l=5.6/22.4=1/4mole
there mass of gas=molar mass×number of moles=64×1/4=16g
therefore molar mass=32×2=64g
since 22.4l=1mole
therefore 5.6l=5.6/22.4=1/4mole
there mass of gas=molar mass×number of moles=64×1/4=16g
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