Question

A gas has volume of 5.0 litre at temperature of 100c° what will be volume if temperature is decrease at 50°c at constant pressure?​

Answer 1

Given :-

→ Initial volume of the gas = 5 L

→ Initial temperature = 100°C

→ Final temperature = 50°C

→ Pressure is constant.

To find :-

→ Final volume of the gas.

Solution:-

Firstly let's convert the initial and final temperature from °C to K .

Initial :-

⇒0°C = 273 K

⇒100°C = 273 + 100

⇒373 K

Final :-

⇒50°C = 273 + 50

⇒323 K

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Now according to Charle's Law, we have :-

V₁/T₁ = V₂/T₂ [Pressure is contant]

⇒5/373 = V₂/323

⇒V₂ = 323 × 5/373

⇒V₂ = 1615/373

⇒V₂ = 4.33 L

∴ Required volume of the gas is 4.33 L .

Answer 2

Given :-

A gas has volume of 5.0 liter at temperature of 100c°

To Find :-

What will be volume if temperature is decrease at 50°c at constant pressure?​

Solution :-

We know that

$\sf 0 \; C = 273 \; K$

So,

100 C = 100 + 273 = 373 K

And

50 C = 50 + 273 = 323 K

Now

$\sf \dfrac{V_1}{T_1} = \dfrac{V_2}{T_2}$

We have

$\begin{cases} \bf V_1 = \frak{5} \\ \bf T_1 = \frak{373} \\ \bf V_2 = \frak{x} \\ \bf T_2 = \frak{323}\end{cases}$

Now

$\sf \dfrac{5}{373} = \dfrac{x}{323}$

$\sf 323(5) = 373(x)$

$\sf 1615 = 373x$

$\sf \dfrac{1615}{373}= x$

$\sf 4.32 = x$