Question

. A gas (ideal) is allowed to expand according to
dP/P=dV/V Select correct relation
(1) du <0
(2) du >0
(3) dQ = 0
(4) du = 0​

Answer 1

Answer:

(2) dU>0

Explanation:

dP/P=dV/V

integrating both sides

lnP=lnV+lnC....where lnC is a constant

P=VC

so it means P is directly proportional to V

now as gas is allowed to expand V increases thus P increases

by PV=nRT

taking n const and R is also const

if P and V increases T also increases

therefore dT>0

now dU= nCvdT

As dT>0 , dU>0

hope it helps u