A gas in a cylinder is at pressure P. If
the masses of all the molecules are made
one third of their original value and
their speeds are doubled, then find the
resultant
pressure.
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2
Answer:
2P
Pressure of gas = P
Mass of molecules is halved and speed is doubled, Thus,
P = 1/3 mn / V . V²ᵣₘₛ
When mass is halved and speed is doubled then
Resultant pressure = Pᵗ = P2/P1 = m2/m1×(v2/v1)²
= (m1/2)/2×(2v1/v1)²
= 2 - P2 = 22P
Pressure of gas = P
Mass of molecules is halved and speed is doubled, Thus,
P = 1/3 mn / V . V²ᵣₘₛ
When mass is halved and speed is doubled then
Resultant pressure = Pᵗ = P2/P1 = m2/m1×(v2/v1)²
= (m1/2)/2×(2v1/v1)²
= 2 - P2 = 2P1 = 2P0
Explanation: mark me as briliant
hope it helps
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