Question

A gas in an open container is heated from 27°C to 127°C.The fraction of the original amount of gas remaining of the container will be what?

Answer 1

We know that, PV = nRT = constant

Where, Pressure P and Volume V are constant, in this case.

n is number of moles

R is gas constant

T is temperature

Given two temperature are 27 and 127 degree celcius

T1 = 27 + 273 = 300 K

T2 = 127 + 273 = 400 K

Therefore, n1T1= n2T2

n1×300=n2×400

n2=3n1 / 4

So, the fraction of moles of the remaining gas in the container after heating will be n2/ n1= 3/4

Answer 2

Answer:

3/4

Explanation:

We know that, PV = nRT = constant

Where, Pressure P and Volume V are constant, in this case.

n is number of moles

R is gas constant

T is temperature

Given two temperature are 27 and 127 degree celcius

T1 = 27 + 273 = 300 K

T2 = 127 + 273 = 400 K

Therefore, n1T1= n2T2

n1×300=n2×400

n2=3n1 / 4

So, the fraction of moles of the remaining gas in the container after heating will be n2/ n1= 3/4