A gas in open container is treated from 27 degree to 127 degree the fraction of original amount of gas remaining
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Explanation:
We know that, PV = nRT = constant
Where, Pressure P and Volume V are constant, in this case.
n is number of moles
R is gas constant
T is temperature
Given two temperature are 27 and 127 degree celcius
T1 = 27 + 273 = 300 K
T2 = 127 + 273 = 400 K
Therefore, n1T1= n2T2
n1×300=n2×400
n2=3n1 / 4
So, the fraction of moles of the remaining gas in the container after heating will be n2/ n1=3/4
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