a gas is allowed to expand in a well insulated container against a constant external pressure of 2.5 ATM from an initial volume of 2.50 L to a final volume of 4.50 litre the change in internal energy Delta u of the gas in joule will be
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Answered by
99
for insulated system
w=-∆u that is q=0.
∆u=-[2.5*10.13*(10)⁴ pas.(4.50-2.50)] jul
w=-∆u that is q=0.
∆u=-[2.5*10.13*(10)⁴ pas.(4.50-2.50)] jul
Answered by
73
"Given:
A gas is allowed to expand in a well insulated container against a constant external pressure of 2.5 ATM from an initial volume of 2.50 L to a final volume of 4.50 litre.
According to question, we will solve in below manner
For insulated system
w=-∆u that is q=0.
∆u=-[2.5*10.13*(10)⁴ pas.(4.50-2.50)] jul.
Therefore, answer the change in internal energy Delta u of the gas in joule will be -[2.5*10.13*(10)⁴ pas.(4.50-2.50)]."
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