Question

A gas is allowed to expand in a well insulated container against a constant

external pressure of 2.5bar from an initial volume of 2.5 L to a final volume of 4.5L

.The change in internal energy , ∆U of the gas will be

a) -500 J
b) + 500 J
c) -1013J
d) + 1013J​

Answer 1

Answer:

Answer-505 J

Explanation:

The change in the internal energy is given by the following expression.

ΔU=q+W

Since container is well insulated, q=0.

Hence, ΔU=W=−PΔV

ΔU=W=−2.5atm×(4.50L−2.50L)

ΔU=W=−5.0Latm

Convert the unit to J

ΔU=W=−5.0Latm×  

1Latm

101.33J

​  

=−505J