Question

A gas is carried through the path AB, BC
and CA according to the adjoining figure.
What is the net work done in the whole
cycle ?
​

Answer 1

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Answer 2

Given :

A gas is carried in a cycle.

To find :

Work done.

Solution :

It is given that a gas is carried through a path

AB, BC and CA.

As it is given that

Body started from A then goes to B then to C and then Again to point A.

So

initial point of movement of gas = A

Final point of movement of gas = A

So

Displacement of system = 0

as body again reached to its initial point and displacement of system is zero.

So

This process is a cyclic process.

In cyclic process, as system returns to its initial process,

The internal energy change in this process is equal to zero.

By first law of thermodynamics :

$\Delta U = Q - W \:$

(equation 1)

Change in internal energy of the system is equal to the difference between Heat given to system and work done by the system.

where

∆U = Change in internal energy.

Q= Heat given to system.

W = Work done by the system.

In this case

∆U =0

so by equation 1.

Work done in this case = Heat given to the system

W = Q