Chemistry, asked by thotyactinnoty, 9 months ago

a gas is collected at a pressure of 95 cm of hg and at a temperature of 50 c to what temperature should it be cooled so that it occupies a volume of 80 percent of its original volume when pressure of the gas is 90 cm of hg

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Answered by Anonymous
9

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Answered by ɪᴛᴢᴛʀᴀɢɪᴄɢɪʀʟ
3

76 cm = 1 atm

95cm = 5/4 atm = 1.25 atm

T = 50⁰C = 323K

cet the no. of mole = 1

PV = nRT

1.25 × v = 1 × 1/12 × 323

v = 323/12 × 1.25 = 21.533

now, new v = 80% of old v

new v = 17.2264

p = 90/76

PV = nRT

= 90/76 × 17.226

= 1 × 1/12 × t

= t( 90 × 17.226 × 12) ÷ 76

= 244.79

=> 244.8 k

hope it helped!! :)

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