A gas is confined in a cylinder with a movable piston at one end when the volume of cylinder is 684ml the pressure of gas is 1.32 atm what will be the pressure if the volume of cylinder is reduced to 568 ml and temperature is constant
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3
Answer:
P1V1=P2V2
684*1.32=P2*568
P2=1.58
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Explanation:
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