Question

A gas is contained in a vertical, frictionless piston-cylinder device. The piston has a mass of 4 kg and a cross-sectional area of 35 cm². A compressed spring above the piston exerts a force of 60 N on the piston. If the atmospheric pressure is 95 kPa, determine the pressure inside the cylinder.(Fig. 2)
​

Answer 1

Answer:

YOUR ANSWER

HOPE IT MAY HELP YOU

Answer 2

Given : mass of piston = 4 kg

           cross-sectional area = 35 $cm^{2}$

           exert force of piston is = 60 N.

           p = 95 kPa

To find atmospheric pressure inside the cylinder

total force acting on the piston = spring force + piston self weight

pressure due to Forces

       $P_{gauge} = \frac{W}{A} +\frac{F}{A}$

            $= \frac{m_{og} }{A} + \frac{F}{A}$

             $= \frac{3.2*9.81}{35*10^{4} } +\frac{110}{35*10^{-4} }$

           $= 8969.143+31428.571$

         $p_{gauge} = 4039.714\\p_{gauge} = 40.398 kPa$

Hence total pressure inside the cylinder $= P_{atm} + P_{gauge}$

                       = 95+40.398

                       = 135.397 Kpa