Science, asked by myself9866, 1 year ago

A gas is cooled from 365 K to 285 K while its volume changes from 12.8 L to 9.9 L. The initial pressure of the gas is 1.9 atm. The final pressure of the gas, rounded to the nearest tenth

Answers

Answered by cherrysurfer028
1
Chakka, Gay,Hijara,mauga.
Answered by Arslankincsem
0

The initial temperature T1 is 365K and Final temperature T2 is 285K.


The initial volume V1 is 12.8L and final volume V2 is 9.9L.


The Final pressure, P2 is 1.9 atm.

Ideal gas equation is PV/T = C.


Therefore, P1V1/T1 = P2V2/T2.


Then P1 = P2V2/T2 x T1/ V1.


When we factor the numbers into the given equation, the answer results in 1.8 atm.

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