Question

A gas is enclosed in a cylinder fitted with frictionless piston according to class xi

Answer 1

For adiabatic process, T1Vγ−11=T2Vγ−12 if ‘a′ is cross-section of vessel then

V1=a.L1andV2=a.L2

So, T1T2=(V2V1)γ−1=(aL2aL1)γ−1=(L2L1)γ−1

Now for monatomic gases, γ(=CpCv)=53

So, T1T2=(L2L1)53−1=(L2L1)23

Ans : (D)