Question

A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at
pressure Pᵢ = 10⁵ Pa and volume Vᵢ = 10⁻³ m³ changes to a final state at P???? = (1/32) x 10⁵ Pa and
V???? = 8 x 10⁻³ m³ in an adiabatic quasi-static process, such that P³ V⁵ = constant. Consider another
thermodynamic process that brings the system from the same initial state to the same final state in two
steps: an isobaric expansion at Pᵢ followed by an isochoric (isovolumetric) process at volume V????. The
amount of heat supplied to the system in the two-step process is approximately
(A) 112 J (B) 294 J
(C) 588 J (D) 813 J

Answer 1

Sorry, I don't know.......

Answer 2

Answer:

Answer -

W = 75 J

● Solution -

# Given -

Pi = 10^5 Pa

Vi = 10^–3 m^3

Pf = (1/32)×10^5 Pa

Vf = 8×10^–3 m^3

# Solution -

Work done is calculated by -

W = -∆(PV)

W = PiVi - PfVf

W = 10^5×10^–3 - (1/32)×10^5×8×10^–3

W = 75 J