A gas is enclosed in a cylinder with a movable frictionless piston.Its initial thermodynamic state at pressure pi
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● Complete question -
Q. A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure Pi = 10^5 Pa and volume Vi = 10^–3 m^3 changes to a final state at Pf = (1/32) × 10^5 Pa and Vf = 8 × 10^–3 m^3 in a process. Estimate the work done in expansion.
● Answer -
W = 75 J
● Solution -
# Given -
Pi = 10^5 Pa
Vi = 10^–3 m^3
Pf = (1/32)×10^5 Pa
Vf = 8×10^–3 m^3
# Solution -
Work done is calculated by -
W = -∆(PV)
W = PiVi - PfVf
W = 10^5×10^–3 - (1/32)×10^5×8×10^–3
W = 75 J
Therefore, work done in expansion is 75 J.
Hope this helped you...
● Complete question -
Q. A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure Pi = 10^5 Pa and volume Vi = 10^–3 m^3 changes to a final state at Pf = (1/32) × 10^5 Pa and Vf = 8 × 10^–3 m^3 in a process. Estimate the work done in expansion.
● Answer -
W = 75 J
● Solution -
# Given -
Pi = 10^5 Pa
Vi = 10^–3 m^3
Pf = (1/32)×10^5 Pa
Vf = 8×10^–3 m^3
# Solution -
Work done is calculated by -
W = -∆(PV)
W = PiVi - PfVf
W = 10^5×10^–3 - (1/32)×10^5×8×10^–3
W = 75 J
Therefore, work done in expansion is 75 J.
Hope this helped you...
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