A gas is filled in a vessel at 27 C . To what temperature should it be heated in order that 1/3 rd of the gas may escape out of the vessel? please solve it step by step
Answers
Answered by
208
Let the P , V and n be the pressure ,volume ,no of moles respectively initialy.
T= 27c= 27 +273 K=300Kelvin
therefore according to ideal gas equation we can write
PV = n R T
PV = n r 300 (T= 300)
n =PV/300r
Now since 1/3rd gas escaped remaining gas = 2n/3
now let T'' = new temperature
PV = 2n/3 rT''
after putting value of n we get
PV = 2 PV/900r r T''
Now eliminating PV from both sides and r r canceled we get
T'' = 900/2 = 450 Kelvin = 450 -273=177 celcius
So ans 450 kelvin or 177 celcius
T= 27c= 27 +273 K=300Kelvin
therefore according to ideal gas equation we can write
PV = n R T
PV = n r 300 (T= 300)
n =PV/300r
Now since 1/3rd gas escaped remaining gas = 2n/3
now let T'' = new temperature
PV = 2n/3 rT''
after putting value of n we get
PV = 2 PV/900r r T''
Now eliminating PV from both sides and r r canceled we get
T'' = 900/2 = 450 Kelvin = 450 -273=177 celcius
So ans 450 kelvin or 177 celcius
Answered by
1
Explanation:
hope it helps..
thanks plz
mark as brainliest
Attachments:
Similar questions