A gas is heated at constant pressure from 27°C to 227°C The percentage
increase in its volume is
Answers
(P1*V1) /T1=(P2*V2) /T2 where P=Pressure, V=Volume and T=Absolute temperature of the gas.
Given, P1=P2=P(say) (Since pressure is constant)
V1=V(say), where V is the initial volume of the gas.
Therefore, V2=2V since final volume is double the initial volume.
T1=(27+273)K=300K
T2=?
Substituting the values obtained,in the gas equation, we have
P*V/300=P*2V/T2
Solving, we get T2=final temperature of the gas=600K or (600–273)degree C or 327 degrees C.
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Given:
Initial Temperature, T1 = 27°C = 300 K
Final Temperature, T2 = 227°C = 500 K
To Find:
The percentage increase in the volume of the gas.
Calculation:
- Let the initial volume of gas be V1 and the final volume be V2.
- According to Charle's law:
V1/T1 = V2/T2
⇒ V1/300 = V2/500
⇒ V2 = (5/3) V1
- Percentage increase in volume = {(V2-V1)/V1} × 100
⇒ Percentage increase = {((5/3) V1 -V1)/V1} × 100
⇒ Percentage increase = 2/3 × 100