Question

A gas is heated at constant volume, what fraction of heat is converted to work.

(a) 1 (b) ½ (c) ¼ (d) zero​

Answer 1

Answer:

zero

Explanation:

According to the given question , the amount of work done is an isochoric thermodynamic process (constant volume) will be zero.

\boxed{ \rm \therefore \: \dfrac{ W}{\Delta Q} = 0}

∴

ΔQ

W

=0

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Answer 2

The fraction of heat, converted to work is zero

Therefore, option (d) is correct.

Explanation:

Given: A gas is heated at constant volume

To find out: The fraction of heat that is converted to work

Solution:

Since the gas is heated at constant volume

The process is isochoric process

The initial volume $(V_i)$ will be equal to the final volume $(V_f)$

Thus,

$V_i=V_f$

Change in volume $\Delta V=0$

Therefore, the work done

$W=PdV=P\times 0=0$

In fact the whole heat will be absorbed to increase the internal energy of the system.

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