Question

a gas is insulated thermally and then allowed to expand against a constant pressure from v1 to v2 .then

Answer 1

Answer:

-505 J

Explanation:

The change in the internal energy is given by the following expression.

ΔU=q+W

Since container is well insulated, q=0.

Hence, ΔU=W=−PΔV

ΔU=W=−2.5atm×(4.50L−2.50L)

ΔU=W=−5.0Latm

Convert the unit to J

ΔU=W=−5.0Latm×1Latm101.33J=−505J

Answer 2

The change in the internal energy is given by the following expression.

The change in the internal energy is given by the following expression.ΔU=q+W

The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.

The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.Hence, ΔU=W=−PΔV

The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.Hence, ΔU=W=−PΔVΔU=W=−2.5atm×(4.50L−2.50L)

The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.Hence, ΔU=W=−PΔVΔU=W=−2.5atm×(4.50L−2.50L)ΔU=W=−5.0Latm

The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.Hence, ΔU=W=−PΔVΔU=W=−2.5atm×(4.50L−2.50L)ΔU=W=−5.0LatmConvert the unit to J

The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.Hence, ΔU=W=−PΔVΔU=W=−2.5atm×(4.50L−2.50L)ΔU=W=−5.0LatmConvert the unit to JΔU=W=−5.0Latm×1Latm101.33J=−505J