Question

A gas is kept in a container at a constant temperature. Initial pressure of the gas is it. If the
olume of container is reduced to 1/4 of its initial volume, then the new pressure will be
1) 1 atm 2) 2 atm
3) 4 atm 4) 3atm​

Answer 1

Answer:

heya friend

Explanation:

i think answer will be 4 atm

Answer 2

Answer:

V2 = V1/4

T1 = T2 = T

P1 = not mentioned (question not clear)

P2 = ?

use formula : $\frac{P1V1}{T1}$ = $\frac{P2V2}{T2}$

$\frac{P1V1}{T}$ = $\frac{P2V1}{4T}$

cancelling T and V1

we get P2 = 4P1

substitute initial pressure P1

All the best