A gas is present at a volume of 10 L at 120⁰C and adiabatic expands up to 20 L volume at a constant pressure of 0.60 atm. Assume that the heat, work, internal energy, enthalpy and temperature change in this process are 2 moles of gas.
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Explanation:when the process is adiabatic then q=0
And dU=W
dU=W=-pdV
=-0.6×10
. =-6
So dU=W=-6
EnthalphyH=dU-nRT
H=-6-2×8.31×126
Solve it my frnd u will get enthalphy change . I think u can understand the process.
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