Chemistry, asked by vinalika20, 7 months ago

A gas mixture contains 160 g O_(2) and 320gO_(3) .The molar ratio of O_(3) to O_(2) in the mixture will be

Answers

Answered by seemajadhav

1

Answer:

6.66:5

Explanation:

160gm O2=5 moles ofO2

320gm O3= 6.66 moles of O3

O3:O2=6.66:5

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