Question

A gas mixture contains 50% helium and 50% methane by volume .What is the percentage by mass of methane in the mixture

Answer 1

woo Molar and volume ratios will be same (i.e) 1 : 1

∴∴ Mass of 1 mole CH4 and He will be 16 and 4g respectively.

Percentage by mass of CH4=MassofCH4/Totalmass×100

=16/20×100

=80%
hope it helps to you.

Answer 2

Answer:

80%

Explanation:

see the above picture if u have any doubt comment me