A gas mixture of nh3 and h2s contains 20mol % of nh3
Answers
The right answer is 40 ml.
The equation for the reaction (Haber process) is
N2 + 3H2 = 2NH3
1 mole of nitrogen combines with 3 moles of hydrogen to produce 2 moles of ammonia.
Equal volumes of two gases at the same temperature and pressure contain the same number of moles (or molecules).
Since nitrogen and the ammonia produced are in the molar ratio of 1:2, their volumes will also be in the same ratio of 1:2.
So, 20 ml of nitrogen on complete conversion will produce 40 ml of ammonia gas.
Answer:
right answer is 40 ml.
The equation for the reaction (Haber process) is
N2 + 3H2 = 2NH3
1 mole of nitrogen combines with 3 moles of hydrogen to produce 2 moles of ammonia.
Equal volumes of two gases at the same temperature and pressure contain the same number of moles (or molecules).
Since nitrogen and the ammonia produced are in the molar ratio of 1:2, their volumes will also be in the same ratio of 1:2.
So, 20 ml of nitrogen on complete conversion will produce 40 ml of ammonia gas.