Question

A gas occupied 20 liters at a pressure of 40.0 mm hg . What is the volume when the pressure is increased to 80.0 mm hg

Answer 1

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QUESTION -

A gas occupied 20 liters at a pressure of 40.0 mm hg .

What is the volume when the pressure is increased to 80.0 mm hg ?

SOLUTION -

This can be easily solved by using the Boyle ' s law.

According to the law ,

$\dfrac{ P_{1} }{ V _{1} } = \dfrac{ P_{2} } { V _ { 2 } }$

Here :

P1 = 40 mm Hg

V1 = 20 litres

P2 = 80 mm Hg

V2 = ?

Substuting into the formula :

$2 = \dfrac{ 80} { V_{2} } \\ \\ V_{2} = 40 \: Litres</p><p>..... .... [ A ]$

Answer 2

Given :-

A gas occupied 20 liters at a pressure of 40.0 mm hg.

To find :-

The volume when the pressure is increased to 80.0 mm hg.

Solution :-

Pressure₁ = P₁ = 40.0 mm hg

Pressure₂ - P₂ = 80.0 mm hg

Volume₁ = V₁ = 20 l

Volume₂ = V₂ = ?           (To be calculated)

Using Boyle's law,

$\displaystyle{\sf{\frac{P_1}{V_1}=\frac{P_2}{V_2} }}$

Substituting the known values :

$\displaystyle{\sf{\frac{40}{20}=\frac{80}{V_2} }}\\\\\displaystyle{\sf{\implies V_2=\frac{80}{2} }}\\\\\boxed{\displaystyle{\sf{\implies V_2=40\ litres}}}$