Question

A gas occupies 0.418 litre at 740 mm of Hg and 27 °C. Calculate :
(a) its volume at STP
(b) molecular weight if gas weighs 3.0 g
(c) new pressure of gas if the weight of gas is increased to 7.5 g and temperature becomes 280 K
d) the volume of vessel at 300 K​

Answer 1

Explanation:

a) volume at STP is always 22.4 litre

b) molecular weight if gas weighs 3.0 g

PV=NRT→PV=M/MW×RT

P=740/760 ATM

T=27°C=300K

VOLUME=0.418L

740/760 × 0.418=3/MW × 0.0821×300

0.407=73.89/MW

0.407Mw=73.89

Mw=73.89/0.407=181.5g

c) pressure=?

M=7.5g,T=280K

Volume remained constant.

PV=NRT→PV=M/MW×RT

P×0.418=7.5/181.5×0.0821×280

P=0.948/0.418=2.27atm

d) Volume=?, T=300K

Others remained constant.

PV=M/MW×RT

740/760×V=3/181.5×0.0821×300

0.973V=0.406

V=0.406/0.973=0.417L

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