Question

A gas occupies 1.56 l at 1.00 ATM what will be the volume of this gas if the pressure becomes 3.00 ATM

Answer 1

The volume of this gas when pressure becomes 3.00 ATM is 0.52 liters .

Given :

Volume of gas at 1 atm is , $V_i=1.56\ liter$ .

We need to find the volume when pressure is 3 atm .

Let , it be $V_f$ .

Let , us assume that the temperature is constant :

Therefore , condition of constant temperature according to gas law is :

$P_iV_i=P_fV_f\\\\V_f=\dfrac{P_iV_i}{P_f}\\\\V_f=\dfrac{1\times 1.56}{3}\\\\V_f =0.52\ liters$

Hence , this is the required solution .

Learn More :

Thermodynamics

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Answer 2

Answer:

The Volume of the gas will be 0.520 L.

Explanation:

We are given:

The first volume of gas is

V1 = 1.56 l

The first gas pressure is

P1 = 1.00 atm

The last gas pressure is

P2 = 3.00

We were asked to find the final amount of gas,

V2 =?

Here we must take into account that the temperature remains constant in the expansion process. Let's use the equation of an ideal gas and enter the given values ​​to find our answer:

PV = nRT

V = nRT / P

V∝1 / P

[Because nRT conditions are all constant]

V2 / V1 = P1 / P2

V2 = P1P2 × V1

[Take P2]

V2 = 1.00 atm / 3.00 atm × 1.56 l

[Engage specified quantity]

V2 = 1.00 / 3.00 × 1.56 l

V2 = 0.520 l

Therefore, the new gas volume may be about 0.520 l.

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