Question

A gas occupies 100cm3 at 0°c and 760mm of Hg. The temperature of the gas is increased by one fifth and pressure is decreased by one fifth times. Calculate the final volume of the gas.​

Answer 1

Given:-

→ Initial volume of the gas = 100 cm³

→ Initial pressure = 760 mm Hg

→ Initial temperature = 0° C = 273 K

To find:-

→ Final volume of the gas

Solution:-

Final temperature :-

= 273 + (1/5 × 273)

= 273 + 54.6

= 327.6 K

Final pressure :-

= 760 - (1/5 × 760)

= 760 - 152

= 608 K

Now according to Combined Gas Law, we know that :-

P₁V₁/T₁ = P₂V₂/T₂

Where :-

• P₁ is the initial pressure.

• V₁ is the initial volume.

• T₁ is the initial temperature.

• P₂ is the final pressure.

• V₂ is the final volume.

• T₂ is the final temperature.

=> 760×100/273 = 327.6×V₂/608

=> 76000/273 = 327.6×V₂/608

=> 76000×608 = 327.6×V₂×273

=> V₂ = 76000×608/327.6×273

=> V₂ = 46208000/89434.8

=> V₂ = 516.67 cm³

Thus, final volume of the gas is 516.67cm³ .

Answer 2

Answer:

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