Question

A gas occupies 500 cm^3 at normal temperature. At what temperature will the volume of the gas reduced by 20% of its original volume, pressure being constant?

Answer 1

Given,

Initial volume of the gas V1 = 500cm3

Normal temperature T1 =273K

Volume is reduced by 20% of the initial volume, i.e volume which mremains is (100-20)% = 80%

Therefore, 80% of 500

                =80100×500=400cm3

Thus V2 =400cm3

      We have to find T2

From Charles Law we know that,

                V1T1= V2T2

Substituting the values we get

                500273=400T2

      Thus T2 =  273×400500

              T2 = 218.4K

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