A gas Occupies 500 cm3 at normal temperature. At what temperature will the volume of the gas be reduced by 20% of it's original volume , pressure being constant ?
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As PV = nRT
P is constant so V is directly proportional to T
V = kT
or , V1/T1 = V2/T2 = k _______(1)
where k is constant of proportionality
As Normal temperature is defined as 20℃ or 293 K
so, T1 = 293 K
V1 = 500 cc
V2 = 500 - 20% of V1 = 500-0.2×500
= 500 - 100 = 400 cc
T2= ??
Putting values in eqn 1 , we get
500/293 = 400/ T2
or, T2 = 400×293 /500 = 293×4/5 K
= 234.4 K
or, 273 - 234.4 = -38.6 ℃
P is constant so V is directly proportional to T
V = kT
or , V1/T1 = V2/T2 = k _______(1)
where k is constant of proportionality
As Normal temperature is defined as 20℃ or 293 K
so, T1 = 293 K
V1 = 500 cc
V2 = 500 - 20% of V1 = 500-0.2×500
= 500 - 100 = 400 cc
T2= ??
Putting values in eqn 1 , we get
500/293 = 400/ T2
or, T2 = 400×293 /500 = 293×4/5 K
= 234.4 K
or, 273 - 234.4 = -38.6 ℃
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