Question

a gas occupies 70 litres at 27 degree Celsius what volume will it occupy at 273 degree Celsius pressure remaining constant

Answer 1

$\huge\underline{\underline{\bf \orange{Question}}}$

A gas occupies 70 litres at 27°C what volume will it occupy at 273°C pressure remaining constant

$\huge\underline{\underline{\bf \orange{Solution}}}$

$\large\underline{\underline{\sf Given:}}$

• Volume ${\sf (V_1)}$ = 70L
• ${\sf T_1=27+273=300K}$
• ${\sf T_2=273+273=546K}$

$\large\underline{\underline{\sf To\:Find:}}$

• Volume ${\sf (V_2)}$

✪$\large{\boxed{\bf \blue{\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}} }}$

$\implies{\sf \dfrac{70}{V_2}=\dfrac{300}{546}}$

$\implies{\sf V_2=\dfrac{70×546}{300} }$

$\implies{\sf V_2=\dfrac{38220}{300}}$

$\implies{\bf \red{V_2=127.5\:L}}$

$\huge\underline{\underline{\bf \orange{Answer}}}$

Volume at 273°C is ${\bf \red{127.5\:L}}$

Answer 2

The volume occupied by the gas at 273°C is 127.4 L

Explanation:

To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=70L\\T_1=27^oC=(27+273)K=300K\\V_2=?L\\T_2=27^oC=(273+273)K=546K$

Putting values in above equation, we get:

$\frac{70}{300K}=\frac{V_2}{546}\\\\V_2=\frac{70\times 546}{300}=127.4L$

Learn more about Charles' law:

https://brainly.com/question/14468528

https://brainly.com/question/9255358

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