Physics, asked by kimiantrenchfield77, 1 month ago

a gas occupies 9.0 L at a temperature of 300k. What is the volume at 405K?

Answers

Answered by rajaryan08082006

1

Answer:

12.15L

Explanation:

V1/T1 = V2/T2

V1 = 9L

T1 = 300K

V2 = ?

T2 = 405K

9/300 = V2 / 405

V2 = ( 9 / 300 ) X 405

V2 = 12.15L

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