Question

A gas occupies 900 mL at a temperature of 27 °C. What is the volume at

132 °C?​

Answer 1

Ideal gas equation:

$\boxed{\rm PV=nRT}$

》Assuming pressure is constant here,

$\rightarrow \rm \dfrac{V}{T} = \dfrac{nR}{P} = constant$

we can say here,

$\bf \dfrac{ V_1}{T_1} = \dfrac{V_2}{T_2}$

-----

Convert the Temp in it SI unit = kelvin.

T1 = 27°+273°= 300K , T2 = 132°+273°= 405K

$\rightarrow\rm \dfrac{ V_1}{T_1} = \dfrac{V_2}{T_2}$

$\rightarrow\rm \dfrac{ 900}{300} = \dfrac{V_2}{405}$

$\rightarrow\rm V_2 = 3\times 405$

$\rightarrow\rm V_2 = 1215\;ml$

☆volume at 132°C is 1215 ml.

Answer 2

Explanation:

Ideal gas equation:

$\boxed{\rm PV=nRT}$

》Assuming pressure is constant here,

$\rightarrow \rm \dfrac{V}{T} = \dfrac{nR}{P} = constant$

we can say here,

$\bf \dfrac{ V_1}{T_1} = \dfrac{V_2}{T_2}$

-----

Convert the Temp in it SI unit = kelvin.

T1 = 27°+273°= 300K , T2 = 132°+273°= 405K

$\rightarrow\rm \dfrac{ V_1}{T_1} = \dfrac{V_2}{T_2}$

$\rightarrow\rm \dfrac{ 900}{300} = \dfrac{V_2}{405}$

$\rightarrow\rm V_2 = 3\times 405$

$\rightarrow\rm V_2 = 1215\;ml$

☆volume at 132°C is 1215 ml.