A gas occupies a volume 'V' litre at 273 K. Find the temperature at which the volume is doubled?
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Double the temperature
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Given,
T1= 273 K
V1= 0.2dm3
T2=2×273=546K(if absolute temperature is doubled at the same pressure)
V2=?
By Charles law,
V2V1=T2T1
V2=273546×0.2dm3
V2=0.4dm3
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