A gas occupies an initial volume of 400cc at pressure 2atm if pressure is changed to 5 atm the volume was found to be 200 cc calculate the value of2atm
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when a gas is held at a constant temperature and mass in a closed container, the volume and pressure vary inversely. The equation to use is
P 1 V 1 = P 2 V 2
Given :-
V 1 = 200
mL × 1
L 1000
mL = 0.2 L P
1 = 700 mmHg
V 2 = 100
mL ×1
L 1000
mL = 0.1 L
Unknown:-
P 2
Equation :-
P 1 V 1 = P 2 V 2
Solution :-
Rearrange the equation to isolate P 2 and solve.
P 2 = P 1 V 1V 2 P 2 = ( 700 mm Hg × 0.2 L )
0.1 L = 1400 L , which must be rounded to
1000 L
because all of the measurements have only one significant figure.
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