Question

a gas occupies volume of 800cm^3 at a pressure of 76 CM of mercury .if the pressure is increased to 80 centimetre of Mercury as the same temperature the volume of the gas will be now .. spam answer will be reported​

Answer 1

Answer:

Temp= 300k

Volume=300cm3 ,=3L

Pressure= 76cm hg ,=76bar

The temperature and pressure at STP are

298 K 1 Atm pressure

So substituting these on the equation

P1 V1 / T1 = P2 V2 / T2

That is

76×3/273 = 1×V2 / 298

That is

V2 = 76×3×298 / 273

= 248.9L

Explanation:

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Answer 2

Given - Initial Volume - 800 cm³

Initial Pressure - 76 cm Hg

Final pressure - 80 cm Hg

Find - Final volume in the given pressure change

Solution - Pressure and volume are related by Boyle's Law. It states are pressure and volume at ideal conditions is constant. The formula relating it is - P*V = constant. Here, p is pressure and V is volume.

According to question, P1V1 = P2V2

Keeping the values in equation-

76*800 = 80*V2

V2 = 760 cm³

Hence, final volume of gas will be 760 cm³.